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    PracticeAQA GCSEAQA GCSE Chemistry Foundation Tier Paper 1Question 09.5
    Medium3 marksStructured
    Quantitative chemistryIsotopesRelative Atomic MassCalculation

    AQA GCSE · Question 09.5 · Quantitative chemistry

    The discovery of isotopes explained why some relative atomic masses are not whole numbers. Element R has two isotopes. Table 5 shows the mass numbers and percentage abundances of the isotopes of element R.
    <br/><br/>

    <div style="font-family: Arial, sans-serif; max-width: 400px;"> <h3 style="text-align: center; margin-bottom: 5px;">Table 5</h3> <table style="width: 100%; border-collapse: collapse; text-align: center; border: 1px solid #000;"> <thead> <tr style="background-color: #ffffff;"> <th style="border: 1px solid #000; padding: 10px; width: 50%;">Mass number</th> <th style="border: 1px solid #000; padding: 10px; width: 50%;">Percentage abundance (%)</th> </tr> </thead> <tbody> <tr> <td style="border: 1px solid #000; padding: 10px;">6</td> <td style="border: 1px solid #000; padding: 10px;">7.6</td> </tr> <tr> <td style="border: 1px solid #000; padding: 10px;">7</td> <td style="border: 1px solid #000; padding: 10px;">92.4</td> </tr> </tbody> </table> </div> <br/><br/>

    Calculate the relative atomic mass (Aᵣ) of element R. <br/><br/>
    Give your answer to 1 decimal place.

    How to approach this question

    1. For each isotope, multiply its mass number by its percentage abundance.\n - Isotope 1: 6 × 7.6\n - Isotope 2: 7 × 92.4\n2. Add the results from step 1 together.\n3. Divide the total sum by 100.\n4. Round your final answer to 1 decimal place.

    Full Answer

    Aᵣ = Σ (isotope mass number × isotope abundance) / 100\nAᵣ = [(6 × 7.6) + (7 × 92.4)] / 100\nAᵣ = [45.6 + 646.8] / 100\nAᵣ = 692.4 / 100\nAᵣ = 6.924\nTo 1 decimal place, Aᵣ = 6.9
    The relative atomic mass (Aᵣ) is the weighted average mass of the isotopes of an element. It is calculated using the following formula:\nAᵣ = Σ (isotope mass number × isotope abundance) / 100\n\nUsing the data from the table:\n- Isotope 1: mass number = 6, abundance = 7.6%\n- Isotope 2: mass number = 7, abundance = 92.4%\n\nStep 1: Multiply each mass number by its abundance.\n(6 × 7.6) = 45.6\n(7 × 92.4) = 646.8\n\nStep 2: Add these values together.\n45.6 + 646.8 = 692.4\n\nStep 3: Divide by 100.\n692.4 / 100 = 6.924\n\nStep 4: Give the answer to 1 decimal place.\nAᵣ = 6.9

    Common mistakes

    ✗ Forgetting to divide by 100.\n✗ Not rounding the final answer to the required number of decimal places.\n✗ Adding the masses and percentages before multiplying.
    Question 09.4All questionsQuestion 10.1

    Practice the full AQA GCSE Chemistry Foundation Tier Paper 1

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