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AQA GCSE · Question 01.4 · Quantitative chemistry
A student heats 2.5 g of hydrated copper sulfate in a test tube. 0.9 g of water is given off. The remaining solid is anhydrous copper sulfate.
Calculate the mass of anhydrous copper sulfate produced.
A student heats 2.5 g of hydrated copper sulfate in a test tube. 0.9 g of water is given off. The remaining solid is anhydrous copper sulfate.
Calculate the mass of anhydrous copper sulfate produced.
How to approach this question
1. Identify the total mass of the reactant (hydrated copper sulfate).
2. Identify the mass of one of the products (water).
3. Apply the law of conservation of mass: total mass of reactants = total mass of products.
4. Subtract the mass of water from the initial mass of hydrated copper sulfate to find the mass of the other product (anhydrous copper sulfate).
Full Answer
Mass of anhydrous copper sulfate = 2.5 g - 0.9 g = 1.6 g
According to the law of conservation of mass, the total mass of the reactants must equal the total mass of the products.
Initial mass (hydrated copper sulfate) = 2.5 g
Mass of products = Mass of anhydrous copper sulfate + Mass of water
2.5 g = Mass of anhydrous copper sulfate + 0.9 g
To find the mass of anhydrous copper sulfate, we rearrange the equation:
Mass of anhydrous copper sulfate = 2.5 g - 0.9 g = 1.6 g
Common mistakes
✗ Adding the masses instead of subtracting.
✗ Incorrectly subtracting the numbers.
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