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Quantitative chemistryHighercalculationpercentage yield

AQA GCSE · Question 01.5 · Quantitative chemistry

The maximum theoretical mass of the salt that could be produced using 50 cm³ of the sulfuric acid is 12.5 g.
The percentage yield of the salt is 92.8%.
Calculate the mass of salt actually produced.
Use the equation:
% yield = (mass of salt actually produced / maximum theoretical mass of salt that could be produced) × 100

How to approach this question

1. Write down the formula for percentage yield. 2. Rearrange the formula to make "mass of salt actually produced" the subject. 3. Substitute the given values for percentage yield (92.8%) and maximum theoretical mass (12.5 g) into the rearranged formula. 4. Calculate the final answer.

Full Answer

mass of salt actually produced = (% yield / 100) × maximum theoretical mass mass of salt actually produced = (92.8 / 100) × 12.5 g mass of salt actually produced = 0.928 × 12.5 g mass of salt actually produced = 11.6 g
The formula for percentage yield is: % yield = (actual yield / theoretical yield) × 100 We are given the % yield (92.8%) and the theoretical yield (12.5 g), and we need to find the actual yield (mass of salt actually produced). First, we need to rearrange the equation to solve for the actual yield. 1. Divide both sides by 100: (% yield / 100) = actual yield / theoretical yield 2. Multiply both sides by the theoretical yield: actual yield = (% yield / 100) × theoretical yield Now, substitute the values: actual yield = (92.8 / 100) × 12.5 actual yield = 0.928 × 12.5 actual yield = 11.6 g

Common mistakes

✗ Multiplying percentage yield by theoretical mass without dividing by 100. ✗ Dividing theoretical mass by percentage yield. ✗ Rounding the answer incorrectly.

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