Medium2 marksStructured
The rate and extent of chemical changeHigherrates of reactionconcentrationlimiting reactant

AQA GCSE · Question 09.4 · The rate and extent of chemical change

Figure 13Time in secondsMoles of hydrogen collected0.0000.0020.0040.0060.0080.0100.0120.0140.0160.018050100150200

The student repeated the experiment using 0.20 mol/dm³ sulfuric acid instead of 0.40 mol/dm³ sulfuric acid. Excess zinc was used in each experiment.
Sketch a line on Figure 13 to show the results you would expect.

How to approach this question

You need to sketch a new line on the graph for a reaction with a lower concentration of acid. Consider two things: the rate of reaction and the total amount of product formed. 1. **Rate of Reaction:** The concentration of sulfuric acid is halved (from 0.40 to 0.20 mol/dm³). According to collision theory, how will this affect the rate of reaction? How is the rate represented on the graph (i.e., the steepness or gradient)? 2. **Total Product:** The zinc is in excess, so the sulfuric acid is the limiting reactant. The concentration of the acid is halved, but the volume is the same. How will this affect the total number of moles of acid reacting, and therefore the total number of moles of hydrogen gas produced? Where should the new line level off compared to the original line?

Full Answer

The sketched line should: 1. Start at the origin (0,0). 2. Be less steep than the original line, showing a slower initial rate of reaction. 3. Level off at exactly half the final height of the original line (at 0.0085 mol), because the concentration of the limiting reactant (sulfuric acid) is halved.
Changing the concentration of a reactant affects both the rate of the reaction and the total amount of product formed if that reactant is limiting. 1. **Effect on Rate:** The concentration of sulfuric acid has been halved. This means there are fewer acid particles per unit volume. According to collision theory, this will lead to fewer frequent successful collisions between the zinc and acid particles. Therefore, the rate of reaction will be slower. On the graph, a slower rate is represented by a less steep gradient. The new line should start at the origin but be shallower than the original line. 2. **Effect on Total Product:** The zinc is in excess, which means the sulfuric acid is the limiting reactant – it will run out first and stop the reaction. Since the volume of acid used is the same but its concentration is halved, there are half the number of moles of sulfuric acid reacting. According to the stoichiometry of the reaction (Zn + H₂SO₄ → ZnSO₄ + H₂), this will produce half the number of moles of hydrogen gas. The original reaction produced approximately 0.017 moles of H₂. Therefore, the new reaction will produce 0.017 / 2 = 0.0085 moles of H₂. The new line must level off at this value on the y-axis.

Common mistakes

✗ Drawing a line that is steeper (faster rate). ✗ Drawing a line that levels off at the same height as the original (implying the same amount of product is made). ✗ Drawing a line that levels off at a height other than half the original. ✗ Not starting the line at the origin (0,0).

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