How could the error in the algorithm in Figure 9 be corrected?

The algorithm uses a nested loop structure to process a list of students and their corresponding scores. The outer loop (controlled by `i`) iterates through the students. The inner loop (controlled by `j`) is intended to iterate through the scores for the current student. The problem states there are three test scores for each student. The error lies in line 7: `FOR j ← 0 TO 1`. This loop only executes for `j=0` and `j=1`. It does not execute for `j=2`, so the third score for each student is never accessed or displayed. To fix this, the loop needs to include `j=2`. The correct syntax is `FOR j ← 0 TO 2`. This will make the loop run three times, correctly processing all three scores for each student.