Figure 16 shows an incomplete algorithm, represented using pseudo-code, designed to output the highest or lowest results of a vote. The programmer has used a two-dimensional array called results to store the genre and the number of votes for each genre. Parts of the algorithm are missing and have been replaced with the labels L1 to L3.

Figure 16
SUBROUTINE showResults(method, numberOfGenres)
results ← [['Pop', 'Post-Punk', 'Techno', 'Metal', 'Dance'],
['7', '19', '14', '1', '9']]
pos ← 0
high ← -1
IF method = 'HIGHEST' THEN
FOR i ← 0 TO numberOfGenres - 1
Votes ← STRING_TO_INT(results[L1][i])
IF votes > high THEN
high ← votes
pos ← L2
ENDIF
ENDFOR
ELSE
OUTPUT 'not yet working'
ENDIF
IF high ≠ -1 THEN
OUTPUT results[0][pos], ' with ', results[1][pos]
ENDIF
ENDSUBROUTINE

OUTPUT 'Show the genre with the HIGHEST or LOWEST number of votes? '
method ← USERINPUT
showResults(L3, 5)
State what should be written in place of the labels L1 to L3 in the algorithm.

This question requires understanding how 2D arrays are indexed and how variables are used within loops and passed to subroutines. - **L1:** `results` is a 2D array (or list of lists). `results[0]` is the list of genres. `results[1]` is the list of vote counts. The line `Votes ← STRING_TO_INT(results[L1][i])` is converting a vote count from a string to an integer. Therefore, it must be accessing the second sub-array, which has an index of 1. - **L2:** The algorithm is a standard "find maximum" routine. It iterates through the list, keeping track of the highest value seen so far (`high`) and the index where it was found (`pos`). The loop variable `i` represents the current index being checked. If `votes` at the current index `i` is greater than the current `high`, we have a new maximum. We must then update `pos` to store this new index, so `pos ← i`. - **L3:** The program asks the user for input and stores it in the `method` variable. This variable is then used to call the `showResults` subroutine. The subroutine definition shows that it accepts `method` as its first parameter. Therefore, the `method` variable must be passed in the call: `showResults(method, 5)`.