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    PracticeAQA GCSEAQA GCSE Maths Higher Tier Paper 2 CalculatorQuestion 10
    Medium3 marksStructured
    NumberHighernumberpercentagesreverse percentages

    AQA GCSE · Question 10 · Number

    384 000 electric cars were sold this year.
    <br>
    This is 20% more than last year.
    <br>
    How many were sold last year?

    How to approach this question

    1. Identify that this is a reverse percentage problem. You are given the final amount after a percentage increase and need to find the original amount. 2. Determine the multiplier for a 20% increase. A 20% increase means you have 100% + 20% = 120% of the original amount. 3. Convert this percentage to a decimal multiplier (120 / 100 = 1.2). 4. Set up an equation: Original Amount × 1.2 = 384 000. 5. Solve for the Original Amount by dividing 384 000 by the multiplier.

    Full Answer

    This problem requires us to find the original value before a percentage increase. This is known as a reverse percentage calculation. The number of cars sold this year (384,000) is 20% *more* than last year. This means that 384,000 represents 100% (last year's amount) + 20% (the increase). So, 384,000 = 120% of last year's sales. To find 100%, we can first find 1% and then multiply by 100, or use a decimal multiplier. Using the multiplier method is faster: 120% as a decimal is 1.2. Let L be the number of cars sold last year. L × 1.2 = 384,000 L = 384,000 ÷ 1.2 L = 320,000 So, 320,000 cars were sold last year.

    Common mistakes

    ✗ The most common mistake is to calculate 20% of 384,000 and subtract it. This would be finding 80% of the current year's sales, not reversing a 20% increase from the previous year. (384,000 × 0.8 = 307,200, which is incorrect). ✗ Dividing by 0.20 instead of 1.20.
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