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    PracticeAQA GCSEAQA GCSE Statistics Foundation Tier Paper 2Question 09.1
    Medium2 marksStructured
    Statistical Measures and CalculationsFoundationprobabilitydata handling

    AQA GCSE · Question 09.1 · Statistical Measures and Calculations

    3117112225133442FOOD TRAY

    Sanders owns a chicken farm where the chickens can roam freely. He is investigating where the chickens tend to go in their field. He divides the field up into 9 squares and counts the number of chickens in each square. Here are the raw data showing how many chickens are in each square. There is a food tray in the bottom right square. What is the probability that a chicken, chosen at random, is in the square with the food tray?

    How to approach this question

    1. Find the number of chickens in the square with the food tray. This is the number in the bottom right square. 2. Calculate the total number of chickens in all 9 squares by adding up all the numbers. 3. The probability is the number of chickens in the food tray square divided by the total number of chickens. 4. Simplify the fraction if possible.

    Full Answer

    42/168 or 1/4
    First, we need to find the total number of chickens on the farm by summing the numbers in all 9 squares: Total chickens = 3 + 11 + 7 + 11 + 22 + 25 + 13 + 34 + 42 = 168. Next, we identify the number of chickens in the square with the food tray, which is the bottom right square. This number is 42. The probability is calculated as: P(in food tray square) = (Number of chickens in food tray square) / (Total number of chickens) P(in food tray square) = 42 / 168. This fraction can be simplified. Both numbers are divisible by 42: 42 ÷ 42 = 1 168 ÷ 42 = 4 So, the simplified probability is 1/4.

    Common mistakes

    ✗ Using 9 as the denominator (number of squares) instead of the total number of chickens.\n✗ Making an error when adding up the total number of chickens.
    Question 08.2All questionsQuestion 09.2

    Practice the full AQA GCSE Statistics Foundation Tier Paper 2

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