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AQA GCSE
AQA GCSEAQA GCSE Maths Higher Cheat Sheet 2026
ExpertMinds Editorial·3 March 2026·10 min read
Practice AQA GCSE questions while you read →Higher tier covers grades 4–9. The content includes everything on Foundation plus significant additional topics. Questions at grades 8 and 9 combine multiple topics in a single question. This cheat sheet focuses on Higher-only content — review the Foundation sheet for baseline rules.
Key fact:Higher grade boundaries are typically: Grade 4 ~15–20%, Grade 7 ~50–60%, Grade 9 ~75–80%. A student who knows all Higher content but is slow will score lower than a student who is fast and accurate on grades 4–7 material.
Quadratics
| Method | Use when | Key step |
|---|---|---|
| Factorising | Coefficient of x² is 1; integer solutions exist | Find two numbers that multiply to c and add to b in x² + bx + c |
| Completing the square | Finding vertex; deriving quadratic formula; always works | x² + bx = (x + b/2)² − (b/2)² |
| Quadratic formula | Always works — use when factorising fails | x = (−b ± √(b²−4ac)) / 2a |
| Discriminant | Number of real roots: b²−4ac > 0 → 2 roots, = 0 → 1, < 0 → 0 | No need to solve — just evaluate b²−4ac |
Trigonometry
| Rule | Formula | Use when |
|---|---|---|
| SOH-CAH-TOA | sin θ = O/H; cos θ = A/H; tan θ = O/A | Right-angled triangles only |
| Sine rule | a/sinA = b/sinB = c/sinC | Non-right triangle: 2 angles + 1 side, or 2 sides + non-included angle |
| Cosine rule | a² = b² + c² − 2bc cosA | Non-right triangle: 2 sides + included angle, or 3 sides (find angle) |
| Area using trig | Area = ½ ab sin C | Any triangle when 2 sides and included angle are known |
Tip:Ambiguous case: when using the sine rule with 2 sides and a non-included angle (SSA), there may be two possible triangles. Check if the second solution (180° − θ) gives a valid triangle by confirming angles sum to less than 180°.
Circle Theorems
Practice AQA GCSE questions while you read
Questions graded, hints, and explained.
- Angle at centre = 2 × angle at circumference (same arc)
- Angles in the same segment are equal
- Angle in a semicircle = 90° (angle subtended by diameter)
- Opposite angles in a cyclic quadrilateral sum to 180°
- Tangent to a circle is perpendicular to the radius at the point of contact
- Two tangents from an external point are equal in length
- Alternate segment theorem: angle between tangent and chord = angle in alternate segment
- Angle between radius and chord (perpendicular from centre bisects chord)
Algebra — Higher Topics
| Topic | Method / rule |
|---|---|
| Algebraic fractions | Factorise numerator and denominator; cancel common factors; find LCM for addition/subtraction |
| Functions: f(x) | f(3) means substitute x = 3 into f(x) |
| Composite functions: fg(x) | Apply g first, then f: fg(x) = f(g(x)) |
| Inverse function: f⁻¹(x) | Replace f(x) with y; rearrange for x; replace x with f⁻¹(x) |
| Iteration | Rearrange to xₙ₊₁ = f(xₙ); substitute repeatedly to converge on root |
| Nth term of quadratic sequence | Second difference ÷ 2 gives coefficient of n²; adjust for linear and constant terms |
| Graph transformations | y = f(x+a): left a; y = f(x)+ a: up a; y = f(ax): squeeze horizontal; y = af(x): stretch vertical |
Practice GCSE Maths Higher questions
Grade 7–9 questions combine multiple topics. Practice multi-step problems to build the fluency needed for the harder marks.
Vectors
- Vector addition: a + b — head to tail; result is the diagonal of the parallelogram
- Scalar multiple: ka — same direction, scaled magnitude
- AB⃗ = b − a (position vectors: from origin)
- Midpoint M of AB: m = ½(a + b)
- To prove collinearity: show vectors are parallel (scalar multiples) and share a common point
- To prove a point divides a line in ratio m:n: express the vector and confirm the ratio
Probability — Higher Topics
| Topic | Rule |
|---|---|
| Conditional probability | P(A|B) = P(A∩B) / P(B) |
| Multiplication rule (dependent events) | P(A and B) = P(A) × P(B|A) |
| Venn diagrams — with algebra | Set up expressions for each region; use total = 1 to solve for unknowns |
| Histograms | Frequency density = Frequency ÷ Class width; area of bar = frequency (not height) |
| Cumulative frequency | Plot upper class boundary vs cumulative frequency; median at n/2; IQR = UQ − LQ |
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