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    PracticeAQA GCSEAQA GCSE Biology Foundation Tier Paper 2Question 02.4
    Medium2 marksStructured
    Homeostasis and ResponseData analysisMean calculationReaction time

    AQA GCSE · Question 02.4 · Homeostasis and Response

    Table 1: Reaction time in millisecondsTestStudent PStudent QStudent RStudent S13173103673202309293352304329031235031543333073593085328312635313Mean315307357X

    Students investigated their reaction times using a computer program. Table 1 shows the results. Calculate mean value X in Table 1.

    How to approach this question

    1. Identify the results for Student S from the table: 320, 304, 315, 308, 313. 2. To calculate the mean, first add all these values together (the sum). 3. Count the number of values (there are 5 tests). 4. Divide the sum of the values by the number of values.

    Full Answer

    312 milliseconds. Working: Sum of results = 320 + 304 + 315 + 308 + 313 = 1560 Mean = Sum / Number of results = 1560 / 5 = 312
    The mean is calculated by summing all the data points and dividing by the number of data points. The reaction times for Student S are: 320, 304, 315, 308, and 313. Step 1: Sum the values. 320 + 304 + 315 + 308 + 313 = 1560 Step 2: Count the number of values. There are 5 values. Step 3: Divide the sum by the count. Mean (X) = 1560 / 5 = 312 milliseconds.

    Common mistakes

    ✗ Making an error in addition. ✗ Dividing by the wrong number (e.g., 4 instead of 5). ✗ Calculating the mean for the wrong student.
    Question 02.3All questionsQuestion 02.5

    Practice the full AQA GCSE Biology Foundation Tier Paper 2

    67 questions · hints · full answers · grading

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