Easy1 markMultiple Choice
The rate and extent of chemical changeHighercatalysttransition metalsContact process

AQA GCSE · Question 07.5 · The rate and extent of chemical change

This reaction uses a catalyst to increase the rate of the reaction. The catalyst is a metal oxide.
Which is the most likely metal in the metal oxide catalyst? Use the periodic table.

Answer options:

A.

Aluminium (Al)

B.

Barium (Ba)

C.

Potassium (K)

D.

Vanadium (V)

How to approach this question

The question asks you to identify the metal in the catalyst for the Contact process (the industrial production of sulfuric acid). 1. Recall which block of the periodic table contains elements that are often good catalysts. 2. Identify which of the options belongs to this block. 3. The specific catalyst for this process is vanadium(V) oxide.

Full Answer

D.Vanadium (V)✓ Correct
The correct answer is Vanadium (V). The catalyst used in the Contact process for making sulfuric acid is vanadium(V) oxide (V₂O₅). Vanadium is a transition metal, and compounds of transition metals often act as catalysts.
The industrial process for making sulfuric acid is called the Contact Process. The key stage is the oxidation of sulfur dioxide to sulfur trioxide: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g). This reaction is slow, so a catalyst is needed to achieve a reasonable rate at the compromise temperature of 450°C. The catalyst used is vanadium(V) oxide, V₂O₅. Vanadium (V) is a transition metal. Transition metals and their compounds are often effective catalysts because they have variable oxidation states, which allows them to facilitate the reaction by providing an alternative reaction pathway with a lower activation energy. The other options are main group metals (Aluminium, Barium, Potassium) whose compounds are not used as catalysts for this reaction.

Common mistakes

✗ Choosing a metal not in the transition block. ✗ Confusing the catalyst for this process with catalysts for other processes (e.g., iron for the Haber process).

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