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    PracticeAQA GCSEAQA GCSE Maths Foundation Tier Paper 1 Non-CalculatorQuestion 18
    Medium3 marksStructured
    Geometry and MeasuresGeometryCoordinatesVectorsStraight Lines

    AQA GCSE · Question 18 · Geometry and Measures

    x y O J (0, 12) K (5, 10) L M

    J (0, 12) and K (5, 10) are points on the straight line JKLM.
    JK = KL = LM
    Work out the coordinates of M.

    How to approach this question

    1. **Find the vector from J to K:** To get from J(0, 12) to K(5, 10), we find the change in x and the change in y. Change in x = 5 - 0 = +5. Change in y = 10 - 12 = -2. So the vector JK is (5, -2). 2. **Use the vector to find the other points:** Since JK = KL = LM, the step from K to L and from L to M is the same vector (5, -2). 3. **Find the coordinates of L:** Start at K(5, 10) and add the vector. L = (5 + 5, 10 - 2) = (10, 8). 4. **Find the coordinates of M:** Start at L(10, 8) and add the vector again. M = (10 + 5, 8 - 2) = (15, 6).

    Full Answer

    The points J, K, L, and M are on a straight line, and the distances between them are equal (JK = KL = LM). This means that to get from J to K, K to L, and L to M, we perform the exact same "step" or vector translation. **Step 1: Find the step from J to K.** - J has coordinates (0, 12). - K has coordinates (5, 10). - To get from x=0 to x=5, we add 5. (Change in x is +5). - To get from y=12 to y=10, we subtract 2. (Change in y is -2). So, the step to get from one point to the next is "go 5 units right and 2 units down". **Step 2: Find the coordinates of L.** We apply this step to the coordinates of K. - K = (5, 10) - L = (5 + 5, 10 - 2) = (10, 8). **Step 3: Find the coordinates of M.** We apply the same step to the coordinates of L. - L = (10, 8) - M = (10 + 5, 8 - 2) = (15, 6). The coordinates of M are (15, 6).

    Common mistakes

    ✗ Making a sign error when finding the change in coordinates (e.g., saying change in y is +2 instead of -2).\n✗ Only applying the step once to find L instead of twice to find M.\n✗ Adding the coordinates instead of finding the difference.
    Question 17All questionsQuestion 19

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