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    PracticeAQA GCSEAQA GCSE Maths Foundation Tier Paper 1 Non-CalculatorQuestion 20.2
    Easy1 markStructured
    AlgebraAlgebraFunction MachineFactorisingFoundation

    AQA GCSE · Question 20.2 · Algebra

    Inputx× 3Outputy

    Complete this number machine so that y = 3x - 24

    How to approach this question

    The equation is y = 3x - 24. The number machine shows that first an operation is performed on x, and then the result is multiplied by 3. This means the machine represents the equation y = 3(x + ?). We can expand this to y = 3x + 3?. Comparing this to the given equation y = 3x - 24, we can see that 3? must be equal to -24. To find the value in the box, we solve for ?: 3? = -24 ? = -24 ÷ 3 ? = -8. So the operation in the first box is "- 8".

    Full Answer

    The first box should be "- 8".
    The number machine shows that the input `x` first goes through an unknown operation, and then the result of that is multiplied by 3 to get the output `y`. Let the unknown operation be represented by a box, so the intermediate value is (x [box]). The final output is y = 3 × (x [box]). We are given that the overall equation is y = 3x - 24. We can factorise the right-hand side of this equation by taking out a common factor of 3: y = 3(x - 8). Now we can compare this with the structure from the number machine: y = 3(x - 8) y = 3 × (x [box]) By comparing these, we can see that the expression in the brackets must be the same. (x - 8) = (x [box]) Therefore, the operation in the box must be **- 8**.

    Common mistakes

    ✗ Putting "-24" in the first box. This would give y = 3(x-24) = 3x - 72, which is incorrect.\n✗ Trying to work backwards and dividing by 3 first, which is not the order shown.
    Question 20.1All questionsQuestion 20.3

    Practice the full AQA GCSE Maths Foundation Tier Paper 1 Non-Calculator

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