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    PracticeAQA GCSEAQA GCSE Maths Foundation Tier Paper 1 Non-CalculatorQuestion 26
    Medium4 marksStructured
    Geometry and MeasuresGeometryAreaCircleRatio

    AQA GCSE · Question 26 · Geometry and Measures

    A large circle and a small circle are shown.
    The radius of the large circle is 12 cm.
    radius of large circle : radius of small circle = 4 : 1
    Work out the shaded area. Give your answer in terms of π.

    How to approach this question

    1. **Find the radius of the small circle:** The ratio is 4 : 1 (large : small). The radius of the large circle is 12 cm, which corresponds to the 4 parts. Value of one part = 12 cm ÷ 4 = 3 cm. The radius of the small circle corresponds to 1 part, so its radius is 3 cm. 2. **Calculate the area of the large circle:** Area = πr². Area_large = π × (12)² = 144π cm². 3. **Calculate the area of the small circle:** Area = πr². Area_small = π × (3)² = 9π cm². 4. **Calculate the shaded area:** Shaded area = Area of large circle - Area of small circle. Shaded area = 144π - 9π = 135π cm².

    Full Answer

    To find the shaded area, we need to calculate the area of the large circle and subtract the area of the small (unshaded) circle. **Step 1: Find the radius of the small circle.** We are given the ratio of the radii: Radius_large : Radius_small = 4 : 1 We know the radius of the large circle is 12 cm. This corresponds to the '4' in the ratio. So, 4 parts = 12 cm. To find the value of 1 part, we divide by 4: 1 part = 12 cm / 4 = 3 cm. The radius of the small circle is 1 part, so Radius_small = 3 cm. **Step 2: Calculate the area of the large circle.** The formula for the area of a circle is A = πr². Area_large = π × (12)² = π × 144 = 144π cm². **Step 3: Calculate the area of the small circle.** Area_small = π × (3)² = π × 9 = 9π cm². **Step 4: Calculate the shaded area.** Shaded Area = Area_large - Area_small Shaded Area = 144π - 9π = 135π cm². The answer is required in terms of π, so this is the final answer.

    Common mistakes

    ✗ Using the radius of the large circle for the small one, or vice versa.\n✗ Making an error when squaring the radii (e.g., 12² = 24).\n✗ Adding the areas instead of subtracting.
    Question 25All questionsQuestion 27.1

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