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    PracticeAQA GCSEAQA GCSE Maths Higher Tier Paper 1 Non-CalculatorQuestion 10.2
    Easy2 marksStructured
    AlgebraInequalitiesSolving InequalitiesAlgebra

    AQA GCSE · Question 10.2 · Algebra

    Solve 5y + 14 ≥ 11

    How to approach this question

    Treat the inequality sign (≥) just like an equals sign (=). 1. Your goal is to get `y` by itself. 2. First, move the constant term (+14) to the other side by subtracting 14 from both sides. 3. Then, divide both sides by the coefficient of `y` (which is 5). The inequality sign only flips if you multiply or divide by a negative number, which is not the case here.

    Full Answer

    Step 1: Isolate the term with y. Subtract 14 from both sides. 5y + 14 - 14 ≥ 11 - 14 5y ≥ -3 Step 2: Solve for y. Divide both sides by 5. y ≥ -3/5 Answer: y ≥ -3/5
    This is a linear inequality. We can solve it using the same methods as for a linear equation. The inequality is: 5y + 14 ≥ 11 1. Subtract 14 from both sides to isolate the term with `y`: 5y + 14 - 14 ≥ 11 - 14 5y ≥ -3 2. Divide both sides by 5 to solve for `y`. Since we are dividing by a positive number (5), the inequality sign does not change direction. y ≥ -3/5 The solution can also be written as y ≥ -0.6.

    Common mistakes

    ✗ Making a sign error when calculating 11 - 14. ✗ Changing the inequality sign to an equals sign in the final answer. ✗ Incorrectly flipping the inequality sign. The sign only flips when you multiply or divide the entire inequality by a negative number.
    Question 10.1All questionsQuestion 11

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