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AQA GCSE · Question 07.4 · Forces
A child is swimming in the pool. The velocity of the child is 0.70 m/s. The child then accelerates for 5.0 s, reaching a final velocity of 1.3 m/s.
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Calculate the acceleration of the child.
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Use the equation:
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acceleration = change in velocity / time taken
A child is swimming in the pool. The velocity of the child is 0.70 m/s. The child then accelerates for 5.0 s, reaching a final velocity of 1.3 m/s.
<br><br>
Calculate the acceleration of the child.
<br>
Use the equation:
<br>
acceleration = change in velocity / time taken
How to approach this question
1. First, calculate the "change in velocity" by subtracting the initial velocity from the final velocity.
2. Identify the "time taken".
3. Substitute these values into the given equation for acceleration.
4. Calculate the result and include the correct units.
Full Answer
change in velocity = 1.3 - 0.70 = 0.6 m/s
acceleration = 0.6 / 5.0
acceleration = 0.12 m/s²
The equation for acceleration is given as: a = Δv / t, where Δv is the change in velocity.
Change in velocity (Δv) = final velocity - initial velocity
Δv = 1.3 m/s - 0.70 m/s = 0.6 m/s
Time taken (t) = 5.0 s
Now substitute these values into the acceleration equation:
Acceleration (a) = 0.6 / 5.0
Acceleration (a) = 0.12 m/s²
The unit for acceleration is m/s².
Common mistakes
✗ Forgetting to calculate the change in velocity first and just using the final velocity (1.3 / 5.0).\n✗ Subtracting the velocities in the wrong order.\n✗ Forgetting the correct units (m/s²).
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