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AQA GCSE · Question 09.6 · Forces
The child applies a force of 2.0 N on gear A. The perpendicular distance between the force and the pivot is 7.5 cm.
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Calculate the moment of the force about the pivot.
The child applies a force of 2.0 N on gear A. The perpendicular distance between the force and the pivot is 7.5 cm.
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Calculate the moment of the force about the pivot.
How to approach this question
1. Use the equation M = Fd.
2. The force (F) is 2.0 N.
3. The distance (d) is 7.5 cm. You must convert this to metres before calculating.
4. Substitute the values and calculate the moment. Include the correct units.
Full Answer
d = 7.5 cm = 0.075 m
M = Fd
M = 2.0 N × 0.075 m
M = 0.15 Nm
The equation for moment is M = Fd.
The values given are:
Force (F) = 2.0 N
Distance (d) = 7.5 cm
The distance must be in metres for the calculation. To convert cm to m, divide by 100.
d = 7.5 / 100 = 0.075 m
Now substitute the values into the equation:
M = 2.0 × 0.075
M = 0.15 Nm
The unit for moment is Newton-metres (Nm).
Common mistakes
✗ Forgetting to convert the distance from cm to m. This is a very common mistake.\n✗ Forgetting the units (Nm).\n✗ Multiplying the numbers incorrectly.
Practice the full AQA GCSE Physics Foundation Tier Paper 2
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