Once the race is run, Angelina notes the order in which the competitors finished, from 1st to 15th position. She also ranks the resting heart rate data from lowest to highest. She calculates that the value of Σd² = 60, where d is the difference in the ranks. Show that the value of Spearman's Rank Correlation Coefficient (SRCC) is 0.89 (to 2 decimal places).
Use SRCC = 1 - (6Σd²) / (n(n² - 1))

This question requires substituting given values into the formula for Spearman's Rank Correlation Coefficient (SRCC) and calculating the result. The formula is: SRCC = 1 - (6Σd²) / (n(n² - 1)) We are given: - The number of competitors, n = 15. - The sum of the squared differences in ranks, Σd² = 60. **Step 1: Substitute the values into the formula.** SRCC = 1 - (6 × 60) / (15 × (15² - 1)) **Step 2: Calculate the numerator.** 6 × 60 = 360 **Step 3: Calculate the denominator.** n(n² - 1) = 15 × (225 - 1) = 15 × 224 = 3360 **Step 4: Substitute these back into the formula.** SRCC = 1 - (360 / 3360) **Step 5: Calculate the fraction and the final value.** SRCC = 1 - 0.107142... SRCC = 0.892857... **Step 6: Round to 2 decimal places.** SRCC ≈ 0.89 The calculation shows that the value of SRCC is 0.89 to 2 decimal places.