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    PracticeAQA GCSEAQA GCSE Biology Foundation Tier Paper 1Question 06.1
    Medium2 marksStructured
    OrganisationFoundationSurface Area to Volume RatioCalculation

    AQA GCSE · Question 06.1 · Organisation

    Table 4JellyfishSize of jellyfishSurface areain mm²Volumein mm³Surface area tovolume ratioA3 6001 200X:1B50 00025 0002:1C1 800 0006 000 0000.3:1D7 500 000125 000 0000.06:1SmallestLargest

    Table 4 shows information about four jellyfish. The jellyfish are listed in order of increasing size.

    Calculate value X in Table 4.

    How to approach this question

    1. Look at the row for jellyfish A. Find the Surface area (3600) and the Volume (1200). 2. The ratio is given as "Surface area to volume ratio". This means you need to calculate Surface Area ÷ Volume. 3. To express the ratio in the form X:1, you divide both sides of the ratio (3600 : 1200) by the second number (1200). 4. Calculate 3600 ÷ 1200 to find the value of X.

    Full Answer

    Surface area = 3600 mm² Volume = 1200 mm³ Ratio = Surface area / Volume = 3600 / 1200 = 3 So the ratio is 3:1. X = 3
    The surface area to volume ratio is calculated by dividing the surface area by the volume. The result is then expressed in relation to 1. For jellyfish A: - Surface area = 3 600 mm² - Volume = 1 200 mm³ To find the ratio, we calculate: Ratio = Surface Area / Volume = 3600 / 1200 To simplify the division, we can cancel the zeros: Ratio = 36 / 12 36 divided by 12 is 3. This means the surface area is 3 times larger than the volume. So, the ratio is 3:1. Therefore, X = 3.

    Common mistakes

    ✗ Dividing volume by surface area (1200 / 3600 = 0.33).\n✗ Making a simple arithmetic error.\n✗ Not understanding how to express a ratio in the form X:1.
    Question 05.8All questionsQuestion 06.2

    Practice the full AQA GCSE Biology Foundation Tier Paper 1

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